Answer it.
Answer it.
Answer it.
Say you looked out into space and saw a galaxy 4.5 billion light years away that turned out to be the Milky Way as it was 4.5 billion years in the past. (This is about the time that the earth was forming.) Given this hypothetical, hyperspherical universe, determine …
A = ∫ 2πr ds
On a flat surface r = s and dr = ds, but since a sphere has positive curvature r < s. Think of s and ds as arc lengths for angles θ and dθ whose vertexes are located at the center of the sphere. Then the radius of a circle on the surface would equal R sin θ and an infinitesimal step away from this circle would equal R dθ; where θ runs from 0 at the origin to π at the antipode.
| π | π | ||||||||
| A = | ⌠ ⌡ |
2π R sin θ R dθ | = | 2πR2 | ⌠ ⌡ |
sin θ dθ | |||
| 0 | π | 0 | |||||||
| A = | 2πR2 | ⎡ ⎣ |
− cos θ | ⎤ ⎦ |
= | − 2πR2 [−1 −1] | |||
| 0 | |||||||||
| A = | 4πR2 | ||||||||
Bump everything up in dimension and watch how this ordinary derivation becomes a hyperderivation by the mere change of a few underlined words.
V = ∫ 4πr2 ds
On a flat surface r = s and dr = ds, but since a hypersphere has positive curvature r < s. Think of s and ds as arc lengths for angles θ and dθ whose vertexes are located at the center of the hypersphere. Then the radius of a spherical shell inside the hypersphere would equal R sin θ and an infinitesimal step away from this sphere would equal R dθ; where θ runs from 0 at the origin to π at the antipode.
| π | π | ||||||||
| A = | ⌠ ⌡ |
4π (R sin θ)2 R dθ | = | 4πR3 | ⌠ ⌡ |
(sin θ)2 dθ | |||
| 0 | π | 0 | |||||||
| A = | 4πR3 | ⎡ ⎣ |
½(θ − cos θ sin θ) | ⎤ ⎦ |
= | 4πR3 [½π − 0] | |||
| 0 | |||||||||
| A = | 2π2R3 | ||||||||
And that's the way it's done.
| R = | C | = | 4.5 billion light years | = 716 million light years |
| 2π | 2π | |||
V = 2π2R3 = 2π2 (716 million light years)3 = 7.25 × 1027 cubic light years
The universe is many times bigger than this, however. No evidence has been found for a distant copy of our region of space out to 13.8 billion light years (the edge of the observable universe). Then there's the matter of the expansion. When we look out to the end of observable space we are also looking back to the beginning of time — we are looking back to an era when the universe was a fraction of its current size. Those places are now many times farther away than they appear to be. Were the universe a hypersphere, its circumference would have to be at least 156 billion light years. For all intents and purposes the universe is essentially flat and may even be infinite in size.