x = t3 − 15t2 + 54t
Where x is in meters, t is in seconds, and positive is forward. Determine …
[magnify]
v = 4t (4 − t) + 8
Assuming the object is located at the origin (s = 0 m) when t = 0 s determine …
| v = | k |
| x | |
v(t) = A(1 − e−bt)
Where v(t) is the instantaneous speed of the car in feet per second, t is the time in seconds, and A and b are constants.| v(1 sec) = 88 ft/sec | and | x(8 sec) = 1320 ft |
The webpage that accompanies this problem has links to images of 50 different time slips — a sampling of the thousands compiled by enthusiasts at dragtimes.com.
| Drag Racing Time Slip — Raw Data | ||||||
| distance | left car time (s) | right car time (s) | ||||
|---|---|---|---|---|---|---|
| (feet) | (miles) | (m) | elapsed | race | elapsed | race |
| 0 | 0 | 0 | 0 | 0 | ||
| 60 | – | 18 | ||||
| 330 | – | 101 | ||||
| 660 | ⅛ | 201 | ||||
| 1000 | – | 305 | ||||
| 1320 | ¼ | 402 | ||||
| Drag Racing Time Slip — Analysis | |||
| quantity | methodology | left car | right car |
|---|---|---|---|
| average speed | |||
| initial speed | |||
| average acceleration | |||
| initial acceleration | |||
| average jerk | |||